数列{an}按下列条件给出:a1=2,当n为奇数时,an+1=an+2,当n为偶数时,an+1=2an,则a2004等于
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数列{an}按下列条件给出:a1=2,当n为奇数时,an+1=an+2,当n为偶数时,an+1=2an,则a2004等于( )
A. 3×21001-2
B. 3×21002
C. 3×21003-2
D. 3×21002-2
A. 3×21001-2
B. 3×21002
C. 3×21003-2
D. 3×21002-2
由an+1=an+2,得an=an+1-2,即当n为奇数时,an=an+1-2,
由an+1=2an,得an=
1
2an+1,即当n为偶数时,an=
1
2an+1,
则a2k-1+a2k=a2k-2+
1
2a2k+1=
1
2a2k+1-2+
1
2(a2k+2-2)=
1
2(a2k+1+a2k+2)-3,
令bk=a2k-1+a2k=
1
2(a2k+1+a2k+2)-3=
1
2bk+1-3
bk+1+6=2(bk+6)成等比,公比为2,a2=4,b1+6=a1+a2+6=12,
bk+6=12×2k-1,即bk=12×2k-1-6=6(2k-1),
则a2003+a2004=b1002=6(21002-1),
a2003=a2004-2,a2003+a2004=2a2004-2=3(21002-1),
故选:C
由an+1=2an,得an=
1
2an+1,即当n为偶数时,an=
1
2an+1,
则a2k-1+a2k=a2k-2+
1
2a2k+1=
1
2a2k+1-2+
1
2(a2k+2-2)=
1
2(a2k+1+a2k+2)-3,
令bk=a2k-1+a2k=
1
2(a2k+1+a2k+2)-3=
1
2bk+1-3
bk+1+6=2(bk+6)成等比,公比为2,a2=4,b1+6=a1+a2+6=12,
bk+6=12×2k-1,即bk=12×2k-1-6=6(2k-1),
则a2003+a2004=b1002=6(21002-1),
a2003=a2004-2,a2003+a2004=2a2004-2=3(21002-1),
故选:C
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