(1) 9x²-25=0 (2)4(2x-1)²=36 (3)(x+1)²-81=0 (4
已知f(x)={x²-3x+4(x>0),{1-x(x
用适当方法解方程(x+6)²-9=0 x²-2x+1=25 4x²+12x+9=81 3x
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
x²+3x-2=0,x²-6x-6=0,3x²-4x-1=0,3x²+10x+3
3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=
(x-2)²=(2x-3)² x²-4x=0 3x(x+1)=3x+3 x²-2
2x(x-1)=0 x²+4=4x (x-3)(x+1)=0 x²-3x+1=0
(X-1)(X-2)=70,(3-X)²+2X(X-1)=0,-3X²-4X+4=0,(3-X)
x²+3x-1=0,1/(x-2)×(x²-4x+4)/(x+1)-(x-1)/(x+2)
解方程 x(x+1)(x²-2x-4)=0 x³-2x+1=0 x的4次方+8x³+14x
解方程 (3x+1)(3x-1)=(x+2)(9x-4) 2(x-3)(x-2)-(x+3)²=(x-1)(x
设f (x)={2x+1(x≥0),x²+4(x