证明:对于函数f(x),若f"(a)存在,则有lim h→0 [f(a+2h)-2f(a+h)+f(a)]/h^2=f"
若函数f(x)在点x=a处可导,则lim(h→0)[f(a+4h)-f(a-2h)]/3h=?
f(x)在x=a处可导, lim(h→0) [f(a+h)-f(a-2h)]/h=
函数f(x)在x=a处可导,则Lim h→a [f(a+3h)-f(a-h)]/2h=?
设函数f(x)在x=a处可导,且lim[f(a+5h)]-f(a-5h)]/2h=1,则f'(a)=
1.函数f(x)在x=a处可导 ,则lim h->a [f(a+3h)-f(a-h)]/2h=?
设f(x)在x=a处可导,f'(x)=b 求极限lim(h-0) f(a-h)-f(a+2h)/ h
若f(x)有二阶导数,证明f''(x)=lim(h→0)f(x+h)-2f(x)+f(x-h)/h^2.
若函数f(x)在x=a处的导数为A,求lim(h→0)[f(a+h)-f(a+2h)]/h的值,
若函数f(x)在点x=a处可导,则lim(h→0)[(f(x)-f(x+3h))/h等于(),求过程
高数有关可导性的判定问题 lim(h->o)(f(a+2h)-f(a+h))/h lim(h->o)(f(a+h)-f(
函数f(x)在x=a处可导,则lim h→0 (f(a+3h)-f(a-h))÷2h=?
举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo