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化简:1/xy+1/(x+4)(y+4)+1/(x+8)(y+8)+.1/(x+4n)(y+4n)

来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/29 17:32:13
化简:1/xy+1/(x+4)(y+4)+1/(x+8)(y+8)+.1/(x+4n)(y+4n)
化简:1/xy+1/(x+4)(y+4)+1/(x+8)(y+8)+1/(x+12)(y+12)+.1/(x+4n)(y+4n)
其中x=4,y=4或x=4,y=8
(1/xy=xy分之一,1/(x+4)(y+4)=(x+4)(y+4)分之一,以此推类)
化简:1/xy+1/(x+4)(y+4)+1/(x+8)(y+8)+.1/(x+4n)(y+4n)
x=y=4 我做不出
x=4,y=8 我做出le
1/xy=(1/x-1/y)*(1/y-x)
1/(x+4)(y+4)=(1/(x+4)-1/(y+4))*(1/y-x)
.以此推类
提取(1/y-x) 原式=( 1/y-x)*(1/x-1/y+1/(x+4)-1/(y+4).1/(x+4n)-1/(y+4n))
因为x=4,y=8
所以 原式=(1/4)*( 1/4 -1/8+1/8 -1/12.1/(4+4n) -1/(8+4n))
=(1/4)*(1/4-1/(8+4n))
=(n+1)/(32+16n)
希望能给你点思路
也希望给我点分.