已知log5(√6+1)+log2(√2-1)=a,则log5(√6-1)+log2(√2+1)=
求下列各式的值 1)log2 6+log2 3 2)lg5+lg2 3)log5 3+log5 三分之一 4)log3
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
比较log2^(1/3),log1/3^2,log5^2的大小
计算:(lg2)2+3lg5+lg5(1+lg2)+lg8+log2(5)log5(4)
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
log5怎么表示(已知log2=a,log3=b)
有关log的数学题①log2(2X+3)=0②log5(X)-1/3log5(8)=0③log2(X)+log4(X)=
(1/log2 10) + (1/log5 10) =lg2 + lg5
1/log2 (11) +1 /log3(11)+1/log4(11)+1/log5(11)
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
2log5(25)-3log2(64)=?