我有二道初二的分式运算题不会做,请指教!
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我有二道初二的分式运算题不会做,请指教!
第一题(a-1+(4a/a-1))(1+a-(4a/a+a),第二题是(x-3/x-2)÷(x+2-(5/x-2)
清楚,不然我看不懂 怎么老师又说第2题是x-(1/3)
第一题(a-1+(4a/a-1))(1+a-(4a/a+a),第二题是(x-3/x-2)÷(x+2-(5/x-2)
清楚,不然我看不懂 怎么老师又说第2题是x-(1/3)
(a-1+(4a/a-1))(1+a-(4a/a+1)
=[(a-1)^2+4a]/(a-1)*[(a+1)^2-4a]/(a+1)
=(a+1)^2/(a-1)*(a-1)^2/(a+1)
=a^2-1
(x-3/x-2)÷(x+2-(5/x-2)
=(x-3/x-2)÷(x^2-4-5)/(x-2)
=(x-3/x-2)/[(x-3)(x+3)/(x-2)]
=x+3
=[(a-1)^2+4a]/(a-1)*[(a+1)^2-4a]/(a+1)
=(a+1)^2/(a-1)*(a-1)^2/(a+1)
=a^2-1
(x-3/x-2)÷(x+2-(5/x-2)
=(x-3/x-2)÷(x^2-4-5)/(x-2)
=(x-3/x-2)/[(x-3)(x+3)/(x-2)]
=x+3