x^2y-y^2z+xz^2-x^2z+xy^2+yz^2-2xyz

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/15 21:19:22

x^2y-y^2z+xz^2-x^2z+xy^2+yz^2-2xyz
=（x² y-x² z）+(xz²+xy²-2xyz)-(y² z-yz²)
=x²(y-z)+x(y²-2yz+z²)-yz(y-z)
=x²(y-z)+x(y-z)²-yz(y-z)
=(y-z)[x²+x(y-z)-yz]
=(y-z)(x+y)(x-z)

(2X+Z-Y)/(X^2-XY+XZ-YZ)-(Y-Z)/(X^2-XY-XZ+YZ) 设x,y,z∈R+,xy+yz+xz=1,证明不等式:(xy)^2/z+(xz)^2/y+(yz)^2/x+6xyz≥x 求(2X+Z-Y)/(X^2-XY+XZ-YZ)-(2X+Y+Z)/(X^2+XY+XZ+YZ) 化简(2x-y-z/x^2-xy-xz+yz)+(2y-x-z/y^2-xy-yz+xz)+(2x-x-y/z^2-xz 分式题:xy=x+y,yz=2(y+z),zx=3(z+x),求xyz/(xy+yz+xz) 已知x+y+z=3,xy+yz+xz=-1,xyz=2,求x^2y^2+y^2z^2+x^2z^2 已知x^3+y^3-z^3=96,xyz=4,x^2+y^2+z^2-xy+xz+yz=12,则x+y-z等于 x^3+y^3+z^3-3xyz变成(x+y+z)(x^2+y^2+z^2-xy-yz-xz)步骤 xy/x+y=1 yz/y+z=2 xz/x+z=3 求xyz/x+y+z=? 因式分解 (x+y+z)^2+yz(y+z)+xyz 实数xyz=1,求证x^2+y^2+z^2+3>=2(xy+xz+yz) 2^x=5^y=10^z(xyz不等于0）求证xy=yz+xz