∫x^2sin(4x)dx 怎么算啊

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∫x^2sin(4x)dx 怎么算啊

∫x^2sin(4x)dx =1/4∫x^2sin(4x)d4x =-1/4∫x^2dcos(4x) =-1/4*x^2cos4x+1/4∫cos4xdx^2 =-1/4*x^2cos4x+1/2∫xcos4xdx =-1/4*x^2cos4x+1/8∫xcos4xd4x =-1/4*x^2cos4x+1/8∫xdsin4x =-1/4*x^2cos4x+1/8*xsin4x-1/8∫sin4xdx =-1/4*x^2cos4x+1/8*xsin4x-1/32∫sin4xd4x =-(1/4)x^2cos4x+(1/8)xsin4x+(1/32)cos4x+C

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