Mathematica画ContourPlot[125*Cos[x]*Tan[y] == 275 + 125*Sin[x
tan(x+y)tan(x-y)=sin^2x-sin^2y/cos^2x-sin^2y 顺便问一下. tan,sin,
y=sin x,y=cos x,y=tan x的单调性
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
mathematica 绘制曲线 y = 638.3 -22.09 *cos(x*0.4916) -27.57*sin(
sin(y+x)+根号3cos(x-y)为偶函数,tan(y)=__________
请问怎么证明sinX+sin(X+Y)+sin(X+2Y)/cosX+cos(X+Y)+cos(X+2Y)=tan(X+
求y=|cosx| y=|tanx| y=sin|x| y=cos|x| y=tan|x|周期
证明(1-2sin x cos x )/(cos^2x-sin^2x)=(1-tan x)/(1+tan x)
如果y=|sin x+cos x+tan x+cot x+sec x+cscx| 那么y的最小值是多少?
证明1-tan^2x/1+tan^2x=cos^2x-sin^2x
f(x)=|sin x+cos x+tan x+cot x+sec x+csc x|最小值
证明:(1 + tan x) / (sin x + cos x) = 1 / cos x