解方程x^2+9x^2/(x-3)^2=16
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/10 21:24:06
解方程x^2+9x^2/(x-3)^2=16
原方程为:x^2+[3x/(x-3)]^2=16
对方程左边进行配方:x^2+2x*3x/(x-3)+[3x/(x-3)]^2=16+2x*3x/(x-3)
合并移项得到:[x+ 3x/(x-3)]^2- 6x^2/(x-3)-16=0
[ x^2/(x-3) ]^2- 6x^2/(x-3)-16=0
把x^2/(x-3) 看作一整体,该方程可因式分解成:
[x^2/(x-3)-8][x^2/(x-3)+2]=0
即x^2/(x-3)-8=0 x^2/(x-3)+2=0
解这两方程,第一方程无解.第二方程的解为:
x1=-1+根号下7 x2=-1-根号下7
对方程左边进行配方:x^2+2x*3x/(x-3)+[3x/(x-3)]^2=16+2x*3x/(x-3)
合并移项得到:[x+ 3x/(x-3)]^2- 6x^2/(x-3)-16=0
[ x^2/(x-3) ]^2- 6x^2/(x-3)-16=0
把x^2/(x-3) 看作一整体,该方程可因式分解成:
[x^2/(x-3)-8][x^2/(x-3)+2]=0
即x^2/(x-3)-8=0 x^2/(x-3)+2=0
解这两方程,第一方程无解.第二方程的解为:
x1=-1+根号下7 x2=-1-根号下7
解方程:(x-2)(x^2-6x-9)=x(x-5)(x-3)
解方程】(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)
解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)
解方程:(x+3)/(x+2)-(x+5)/(x+4)=(x+7)/(x+6)-(x+9)/(x+8)
解方程(x-2)X(x的平方-6x-9)=x(x-5)X(x-3)
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
解方程:2x(x-9x)+16=0
16(x-2)*(x-2)=9(x+3)*(x+3)的方程怎么解
解方程:x^2/9+16/x^2=10/3(x/3-4/x)
解方程 (X-3)(X^2+3X+9)-X(X^2+3)-9=9
解方程:2x+9/x+3 - 1/x-3 = 5 - 3x-2/x
解方程 :(2x-3)(-2x-3)+9x=x(3-4x)