log9 3+log9 27=怎么求~

求x,y值.6log9^x+3log27^y=8log3^x+2log9^y=2 log9^8×log4^27=____. 已知log9 5=a,log9 7=b,求log35 9的值 log9(45)-log9(5) 若log2^3×log3^4×log4^x=log9^3 ,求x log9的5次=a,log9的7次=b,求log35的9次, （log2 3+log4 27）*（log3 4+log9 8）= log2 根号2+log9 27+4^log4 13=? 计算:(1/4)^log4^1/3-lg25-lg4-log9^27 计算:(log4 3+log8 3)×log9 √2=? log3(5)+log9(5)求大神帮助 log4^27×log(8)25×log9^5