(a-2)*(a-3)+2(a+3)*(a-5),其中a=3又1/2 (y-2)*(y^2-6y-9)-y(y^2-2y
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/24 07:21:33
(a-2)*(a-3)+2(a+3)*(a-5),其中a=3又1/2 (y-2)*(y^2-6y-9)-y(y^2-2y-15),其中y=1/2
运用整式的乘法——多项式乘多项式 解答
运用整式的乘法——多项式乘多项式 解答
(a-2)(a-3)+2(a+3)(a-5)
=a^2-5a+6+2(a^2-2a-15)
=a^2-5a+6+2a^2-4a-30
=3a^2-9a-24
=3×49/4-9×7/2-24
=147/4-63/2-24
=147/4-126/4-24
=21/4-24
=-75/4
(y-2)(y^2-6y-9)-y(y^2-2y-15)
=y^3-6y^2-9y-2y^2+12y+18-y^3+2y^2+15y
=-6y^2+18y+18
=-6×1/4+18×1/2+18
=-3/2+9+18
=-3/2+27
=25.5
=a^2-5a+6+2(a^2-2a-15)
=a^2-5a+6+2a^2-4a-30
=3a^2-9a-24
=3×49/4-9×7/2-24
=147/4-63/2-24
=147/4-126/4-24
=21/4-24
=-75/4
(y-2)(y^2-6y-9)-y(y^2-2y-15)
=y^3-6y^2-9y-2y^2+12y+18-y^3+2y^2+15y
=-6y^2+18y+18
=-6×1/4+18×1/2+18
=-3/2+9+18
=-3/2+27
=25.5
因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)(
1.计算(a^2+a+1)(a^2-a+1) 2.计算(x-y)(x+y)+(3x-2y)(2x+y)-x(6x-y)
计算:"3y/x+y"+"y/y-x"+"2x/x^2-y^2" "a+2/a^2-4a+4"-"1/2a+4"-"a-
(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)
两条化简数学题:a^2(y-3)+a(3-y)+7(y-3)3a(2a-5)-(2a-5)
(1/2)已知实数x,y,a满足:根号(x+y-8)+根号(8-x-y)=根号(3x-y-a)+根号(x-2y+a+3)
已知集合A={(x,y)|(y-3)/(x-2)=a+1}B={(x,y)|(a^2-1)x+(a-1)y=15},当a
定义a⊙b=2a-b,求[(x+y)⊙(x-y)]⊙(x-2y)的值,其中x=3,y=5/2.
已知集合A{y/y平方-(a*a+a+1)y+a(a*a+1)>0} B{y/y=1/2x平方-x-5/2,0≤x≤3}
设A={(x,y)}|3x+2y|.
A.A+(4X+3Y)B.A+(4X+6Y) C.A+2(
#include main() {int y,a; y=2,a=1; while(y--!=-1) {do{a*=y;a