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输入一个时间数值,再输入秒数 n,输出该时间再过 n 秒后的时间值,时间的表示形式为时:分:秒,

来源:学生作业帮 编辑:大师作文网作业帮 分类:综合作业 时间:2024/11/19 20:56:29
输入一个时间数值,再输入秒数 n,输出该时间再过 n 秒后的时间值,时间的表示形式为时:分:秒,

#include <stdio.h>
struct time{
    int hour,minute,second;
};
void timecal(struct time *p,int n);
int main(void)
{
    int n;
    int repeat,ri;
    struct time time;
    scanf("%d",&repeat);
    for(ri = 1; ri <= repeat; ri++){
        scanf("%d:%d:%d",&time.hour,&time.minute,&time.second);
        scanf("%d",&n);
        timecal(&time,n);
        printf("time:%d:%d:%d\n",time.hour,time.minute,time.second);
}
void timecal(stuct time*p,int n);
{
     if(time.second+n<60)time.second+=n;
     else if(time.second+n==60){
             time.second=0;
             time.minute++;
             if(time.minute==60){
                time.minute=0;
                time.hour++;
                if(time.hour==24)
                   time.hour=0;
             }
      }
          else{
               time.second=(n+time.second)%60;
               if((time.minute+(time.second+n)/60)<60)
                  time.minute+=(time.second+n)/60;
                  else if((time.minute+(time.second+n)/60)==60){
                          time.minute=0;
                          time.hour++;
                          if(time.hour==24)
                             time.hour=0;
                  }
                  else{
                       time.minute=(time.minute+(time.second+n)/60)%60;
                       if((time.hour+(time.minute+(time.second+n)/60)/60)<24)time.hour=0;
                       else time.hour=(time.hour+(time.minute+(time.second+n)/60)/60)%24;
                  }
           }
 
}                   
程序有点问题,求修正,另外有木有大神有更简单的程序分享
输入一个时间数值,再输入秒数 n,输出该时间再过 n 秒后的时间值,时间的表示形式为时:分:秒,
#include <stdio.h>
struct time{
    int hour, minute, second;
};
void timecal(struct time *p, int n)
{
\x09p->second += n;
\x09if (p->second>=60)
\x09{
\x09\x09p->minute += p->second/60;//60s一分钟
\x09\x09p->second %= 60;//余数为当前秒数\x09\x09
\x09}
\x09if(p->minute>=60)
\x09{
\x09\x09p->hour += p->minute/60;//60分一小时
\x09\x09p->minute %=60;//余数为当前分钟数
\x09}
\x09if (p->hour>=24)
\x09{
\x09\x09p->hour %= 24;//余数为当前小时
\x09}
}
int main(void)
{
    int n;
    int repeat, ri;
    struct time time;
    scanf("%d", &repeat);
    for(ri = 1; ri <= repeat; ri++){
        scanf("%d%d%d", &time.hour, &time.minute, &time.second);
        scanf("%d",&n);
        timecal(&time,n);
        printf("time: %d:%d:%d\n", time.hour, time.minute, time.second);
\x09}
\x09\x09
\x09return 0;

//测试无误