上x1+x2+x3+4x4-3x5=0 中2x1+x2+3x3+5x4-5x5=0 中x1-x2+3x3-2x4-x5=
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上x1+x2+x3+4x4-3x5=0 中2x1+x2+3x3+5x4-5x5=0 中x1-x2+3x3-2x4-x5=0 下3x1+x2+5x3+6x4-7x5=0
急,
急,
x1+x2+x3+4x4-3x5=0
2x1+x2+3x3+5x4-5x5=0
x1-x2+3x3-2x4-x5=0
3x1+x2+5x3+6x4-7x5=0
(1 1 1 4 -3
2 1 3 5 -5
1 -1 3 -2 -1
3 1 5 6 -7)
(1 1 1 4 -3
0 -1 1 -3 1
0 -2 2 -6 2
0 -2 2 -6 2)
(1 1 1 4 -3
0 1 -1 3 -1
0 0 0 0 0
0 0 0 0 0)
(1 0 2 1 -2
0 1 -1 3 -1
0 0 0 0 0
0 0 0 0 0)
所以
x1=-2x3-x4+2x5
x2=x3-3x4+x5
x3=x3
x4= x4
x5= x5
通解为:
x=c1(-2,1,1,0,0)+c2(-1,-3,0,1,0)+c3(2,1,0,0,1)
再问: x4= x4 x5= x5 ?
再答: 我为了通解好写,作的处理,你也可以这样做: 取x3=1,x4=0,x5=0,得一特解(-2,1,1,0,0) 取x3=0,x4=1,x5=0,得一特解(-1,-3,0,1,0) 取x3=0,x4=0,x5=1,得一特解(2,1,0,0,1) 然后得通x=c1(-2,1,1,0,0)+c2(-1,-3,0,1,0)+c3(2,1,0,0,1)
2x1+x2+3x3+5x4-5x5=0
x1-x2+3x3-2x4-x5=0
3x1+x2+5x3+6x4-7x5=0
(1 1 1 4 -3
2 1 3 5 -5
1 -1 3 -2 -1
3 1 5 6 -7)
(1 1 1 4 -3
0 -1 1 -3 1
0 -2 2 -6 2
0 -2 2 -6 2)
(1 1 1 4 -3
0 1 -1 3 -1
0 0 0 0 0
0 0 0 0 0)
(1 0 2 1 -2
0 1 -1 3 -1
0 0 0 0 0
0 0 0 0 0)
所以
x1=-2x3-x4+2x5
x2=x3-3x4+x5
x3=x3
x4= x4
x5= x5
通解为:
x=c1(-2,1,1,0,0)+c2(-1,-3,0,1,0)+c3(2,1,0,0,1)
再问: x4= x4 x5= x5 ?
再答: 我为了通解好写,作的处理,你也可以这样做: 取x3=1,x4=0,x5=0,得一特解(-2,1,1,0,0) 取x3=0,x4=1,x5=0,得一特解(-1,-3,0,1,0) 取x3=0,x4=0,x5=1,得一特解(2,1,0,0,1) 然后得通x=c1(-2,1,1,0,0)+c2(-1,-3,0,1,0)+c3(2,1,0,0,1)
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