大师作文网(1-lg3)(lg8+lg√27-lg√1000)/lg0.3lg1.2
来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/11/19 04:58:29
(1-lg3)(lg8+lg√27-lg√1000)/lg0.3lg1.2
(1-lg3)(lg8+lg√27-lg√1000)/lg0.3lg1.2
=(1-lg3)(lg2^3+lg3^3/2-lg10^3/2)/[(lg3-1)(lg12-1)]
=(1-lg3)(lg2^3+lg3^3/2-lg10^3/2)/[(1-lg3)(1-lg12)]
=(lg2^3+lg3^3/2-lg10^3/2)/(1-lg12)
=(3lg2+3/2*lg3-3/2*lg10)/(1-lg12)
=(3lg2+3/2*lg3-3/2)/(1-lg12)
=(3/2*lg2^2+3/2*lg3-3/2)/(1-lg12)
=(3/2*lg4+3/2*lg3-3/2)/(1-lg12)
=[3/2*lg(4*3)-3/2]/(1-lg12)
=[3/2*lg12-3/2]/(1-lg12)
=3/2(lg12-1)/(1-lg12)
=-3/2(1-lg12)/(1-lg12)
=-3/2
=(1-lg3)(lg2^3+lg3^3/2-lg10^3/2)/[(lg3-1)(lg12-1)]
=(1-lg3)(lg2^3+lg3^3/2-lg10^3/2)/[(1-lg3)(1-lg12)]
=(lg2^3+lg3^3/2-lg10^3/2)/(1-lg12)
=(3lg2+3/2*lg3-3/2*lg10)/(1-lg12)
=(3lg2+3/2*lg3-3/2)/(1-lg12)
=(3/2*lg2^2+3/2*lg3-3/2)/(1-lg12)
=(3/2*lg4+3/2*lg3-3/2)/(1-lg12)
=[3/2*lg(4*3)-3/2]/(1-lg12)
=[3/2*lg12-3/2]/(1-lg12)
=3/2(lg12-1)/(1-lg12)
=-3/2(1-lg12)/(1-lg12)
=-3/2
【根号(lg3的平方-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
根号下｛（lg3)平方-lg9+1｝乘以（lg根号下27+lg8-lg根号下1000）再整体除以lg0.3乘以lg1.2
【根号(lg的平方3-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
(lg√27+lg8-3lg√10)/lg1.2
【根号lg9-lg9+lg10×（lg根号27+lg8-lg根号1000）】÷（lg0.3）（lg1.2）
(lg根号下27+lg8-lg根号下1000)/(1/2lg0.3+lg2)
急(lg根号下27+lg8-lg根号下1000）\lg1.2=（3/2lg3+3lg2-3/2)/lg1.2然后呢
计算：（lg√27+lg8+3lg√10）/lg1.2
（lg根号27+lg8-lg根号1000）/lg1、2
解对数函数lg5(lg8+lg1000)+(lg2^√3)^2+lg(1/6)+lg0.06
(lg8+lg1000)lg5+3(lg2)^2+lg^-1+lg0.006
(lg根号27+lg8-3lg根号10)/lg3+2lg2-1