lim (π/2-arctanx)/1/x x大于0

求lim x趋向于0(arctanx)/(x^2+1) 用洛必达法则解lim(X趋正无穷)((π/2)-arctanx)/(1/x)lim(X趋0)(ln(1+sin2x))/ 求lim arctanx-x/ ln(1+3x+2x^3),x趋于0? lim(2/πarctanx)^x x→∞ lim x^2 e^(1/x^2) x→0 用罗比达求极限. lim(x→+∞)(2/π*arctanx)^x求极限 lim(x→+∞)(π/2-arctanx)/sin1/x, lim（x→∞）x（π/2-arctanx） 一.x---->0时,证明lim(arctanx)/x=1 lim x趋近于0+ (1/x-(1-πx)/arctanx) lim x趋近于0 （arctanx-x）/ln(1+2x^3)答案是多少? 求极限lim(x→0)sinxsin(1/x);lim(x→∞)(arctanx/x) 洛必达求极限 limsinxlnx x趋近于0+,lim(2/π·arctanx)^x x趋近无穷大,lim(ln1(/