知数列{an}满足a1=-2,an+1(下标）=2+2an/(1-an),则an为?

数列{an},a1=2,an+1(下标)=an下标+n+1 求通项an下标 若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点（an,an+ 数列an满足a1=2,an+1=4an+9,则an=? 已知数列{an}满足a1=1,an+1=2an+1 1）求证：数列{an+1}为等比数列； 2) 求{an}的通项an 已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列 已知数列｛an｝满足a1=1,an+1=2an/（an+2）（n∈N+）,则数列｛an｝的通项公式为 已知数列an中 a1=-2且an+1=sn（n+1为下标）,求an,sn 数列{an}满足a1=1,an=an-1（1+2an)（n-1是下标).1、求证:｛1/an｝是等差数列;2、若a1a2 已知数列{an}满足a1=2,an+1=2an/an+2,则an等于多少 一直数列{an}满足a1=0,an=（an-1 +4）/(2an-1) ,求 an 数列an中,a1=3,an+1=an/2an+1,则an=? 数列{an}满足a1=1 an+1=2n+1an/an+2n