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A level A particle of mass 2kg is acted upon by a horizontal

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A level
A particle of mass 2kg is acted upon by a horizontal force of magnitude 10N for 8 seconds,in which time time it moves from rest until it is travelling with speed v米每秒.Show that v=40.The particle continues to move with this speed for the next 10 seconds.It is then brought to rest by the application of a constant resisting force of magnitude x newtons.The total distance travelled is 800m.Find the time for which the particle is decelerating,and the value of X
A level A particle of mass 2kg is acted upon by a horizontal
v1-v0=at,
so,a=40/8=5(m*s^-2)
s1=v0*t+1/2*at^2=0.5*5*64=160m
s2=vt=40*10=400m
so,s3=800-400-160=240m
Because the particle is acted by a constant force:
v1^2-v0^2=2as
so,a2=-64/(2*240)=-0.133(m*s^-2)
so t=8/0.133=60s
x=ma=2*0.133=0.26N
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