a1=5/2 a(n+1)=an/2+2/an ⑴求证：2

绝对难度一道数列题：a1=5/2 a(n+1)=an/2+2/an ⑴求证：2 设数列{an},a1=3,a(n+1)=3an -2 (1)求证:数列{an-1}为等比数列 数列A1=1/3,An+1=An+An²/n²求证An>1/2+1/4n 已知数列{an}满足a1=1,a(n+1)=3an+2(n属于N) 1.求证数列{an+1}是等比数列 2.求{an}的 数列{an} {bn}满足：a1=0 a2=1 a(n+2)=[an+a(n+1)]/2 bn=a(n+1)-an 求证 a1=1,a2=3,a下标(n+2)=a下标(n+1)-2an,求证{a下标(n+1)-an}为等比数列,并求出an 已知数列{An}满足A1=1,An+1=2An+2^n.求证数列An/2是等差数列 设数列{an}中,a1=2,a(n+1)=an+n+1,求an 求助高中数学题已知a1=1/2,a(n+1)=an/(2an+3),求证a1+a2+a3+.+an 在数列｛an}中,a1=2,a(n+1)=an+2^n+1?(1)求证：数列｛an-2^n}为等差数列；?(2)设... 在数列{an}中,已知a1=-1,an+a(n+1)+4n+2=0 (1)求bn=an+2n,求证：{bn}为等比数列 高中数列{An}前n项和Sn且A1=0 ,S(n+1)=4An+2.求证{A（n+1）-2An}为等比数列.