(x-2)^2+(y-2)^2=1 ,x^2+Y^2-x-y+12=0 这个方程组解出来是多少

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(x-2)^2+(y-2)^2=1
x^2+Y^2-x-y+12=0
x^2+Y^2-4x-4y+8=1
x^2+Y^2-x-y+12=0
x^2+Y^2-x-y+12=0
x^2-x+Y^2-y+12=0
x^2-x+1/4-1/4+Y^2-y+1/4-1/4+12=0
(x-1/2)^2-1/4+(y-1/2)^2-1/4+12=0
(x-1/2)^2+(y-1/2)^2+12-1/4-1/4=0
(x-1/2)^2+(y-1/2)^2+23/2=0
(x-1/2)^2+(y-1/2)^2+23/2=0
(x-1/2)^2+(y-1/2)^2+23/2>0
题意矛盾
该方程组无解

解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7 3/x+y+2/x-y=6,3（x+y)-2(x-y)=28解这个方程组 x+6=y-x-8,2x+3y-1=y-x-8 解这个方程组解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12) y/3-x+1/6=3,2(x-y/2)=3(x+y/18) 解这个方程组解方程组｛ 3x-4y(x-y)=3 { 2x-3y=1 解方程组（1）2x+3y=12 ,2x+y=0 (2)x+y=7,3（x+y）-7y=7 x/2=y+1/3 3x+2y=10 这个方程组怎么解? 5x-6y=1,2x-6y=10这个方程组怎么解? 解方程组x^2-y^2=x+y 4x^2-y^2+2x-y=0过程数学书解方程组{2(x+y)-(x-y)=3,（x+y)-2(x-y)=1 解方程组：2(x-y)/3-x+y/4=-1 ,6(x+y)-4(2x-y)=16