f(x)=sin(2x)+cos(2x)+1是怎么化成√2sin(2x+π/4)+1

Sin^x怎么变化成 1-cos(2x) /2 化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x) 函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1 已知函数f(x)=(1+1/tanx)sin(x)^2 -2sin(x+π/4)*cos(x+π/4) 已知f(x)=cos^2x/1+sin^2x求f'(π/4) 求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x). 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2 已知函数f(x)=sin²(π/4+x)+cos²x+1/2求最值 f(x)=(1+cos2x)/[4sin(pai/2+x)]-asin(x/2)cos(pai-x/ 已知f(x)=sin(x/2) + cos(x/2) +[cos(x/2)]^2-1/2 化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1 已知函数f(x)=2Cos x(Sin x-Cos x)+1