根号下2/4sin(π/4-x)+根号下6/4cos(π/4-x)
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根号下2/4sin(π/4-x)+根号下6/4cos(π/4-x)
√2/4 sin(π/4-x)+√6/4 cos(π/4-x)
=√2/2 [1/2 sin(π/4-x)+√3/2 cos(π/4-x)]
=√2/2 [cosπ/3 sin(π/4-x)+sinπ/3 cos(π/4-x)]
=√2/2sin(π/4-x+π/3)
=√2/2sin(7π/12-x)
=√2/2sin(π/2+π/12-x)
=√2/2cos(π/12-x)
再问: 倒数第二步怎么来的啊
再答: 7π/12 =6π/12+π/12 =π/2+π/12 然后再用诱导公式 sin(π/2+a)=cosa
=√2/2 [1/2 sin(π/4-x)+√3/2 cos(π/4-x)]
=√2/2 [cosπ/3 sin(π/4-x)+sinπ/3 cos(π/4-x)]
=√2/2sin(π/4-x+π/3)
=√2/2sin(7π/12-x)
=√2/2sin(π/2+π/12-x)
=√2/2cos(π/12-x)
再问: 倒数第二步怎么来的啊
再答: 7π/12 =6π/12+π/12 =π/2+π/12 然后再用诱导公式 sin(π/2+a)=cosa
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