0.5x+3y+5z=100 x+y+z=100
x/2=y/3=z/5 x+3y-z/x-3y+z
(x+y-z)(x-y+z)=
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知5x+3y+1/3z=100 7x+y+z=100 那么x+y=?
X+Y+Z=100 0.5X+3Y+5Z =100这个方程咋解 X+Y+Z=100 0.5X+3Y+5Z =100这个方
x+y+z=100 0.5x+3y+5z=100 这个方程咋解
X+Y+Z=?
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
已知3X=4X,5Y=6Z求X+Y:Y+Z
若{x+3y+10z=0 则 (x+y-z)/(x-y+z)
100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198 怎么解
解三元一次方程组,100x+10y+z=27(x+y+z) {x+y-z=1 (100z+10y+x)-(100x+10