lim[(4+7+...+3n+1)/(n^2-n)]=

lim(1/n^2+4/n^2+7/n^2+…+3n-1/n^2) lim 1+4+7+...+(3n-2)/n(n+1)=______ lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 求极限 lim(n->无穷)[(3n^2-2)/(3n^2+4)]^[n(n+1)] 求lim(n+1)(n+2)(n+3)/(n^4+n^2+1) 一道极限题,lim[n^2(2n+1)]/(n^3+n+4)n->∞ lim 9^n+4^n+2/5^n-3^2n-1 n趋于无穷大时 lim(n->∞){1/2*4+1/3*5+...+1/(n+1)(n+3)=? lim(x→∞）1+2+3+…+n/(n+2)(n+4)=? lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5 求极限,lim(1+n)(1+n^2)(1+n^4)-----(1+n^2n)=?（n趋于无穷） 求极限：lim(x→无穷)(2^n-7^n)/(2^n+7^n-1)=?