lim(x→0)(a^2x-1)/4x

求极限lim[(a^x+b^x)/2]^1/x (x→0)a>0,b>0 lim【x→0】[(a^x+b^x)/2]^( lim(x→∞)[(a x^2)/x+1]+bx=lim(x→∞)(a x^2)+bx(x+1) / x+1=lim(x 几道求极限的高数题,lim1/x(tanπx/(2x+1)) x→∞lim x(x^x-1)x→0+lim(x^x^x- lim(x→0)ln(1-2x)/x lim(x→0)(1-x^2-e^-x)/sinx 极限lim(x→0)(1-2/x)^x 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(x→0)[（3x+1)/(4x-2)]^1/x 这道题怎么算极限 洛必达法则(1)条件?(2)lim(x->0)P(x)/Q(x)=?已知:lim(x->0)P(x)=A(x),lim( 当x→0时,lim[ln(1-2x)+xf(x)]/x^2=4,求lim[f(x-2)]/x 求极限lim[(a^x+b^x)/2]^1/x (x→0)a>0,b>0 lim(x->0)((2-x)/(3-x))^1/x