当x=-3/5,y=2/3时,求式子[(2x/2x+y)-(4X^2/4x^2+4xy+y^2)]/[(2x/4x^2-
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当x=-3/5,y=2/3时,求式子[(2x/2x+y)-(4X^2/4x^2+4xy+y^2)]/[(2x/4x^2-y^2)+(1/y-2x)]
[(2x/2x+y)-(4X^2/4x^2+4xy+y^2)]/[(2x/4x^2-y^2)+(1/y-2x]
=[(4x^2-4x^2+2xy)/(2x+y)^2]/{(2x-2x+y)/[(2x+y)(2x-y)]}
=2x*(2x-y)/(2x+y)
把x=-3/5,y=2/3代入,得:
-2*3/5*(-2*3/5-2/3)/(-2*3/5+2/3)
=-21/5
=[(4x^2-4x^2+2xy)/(2x+y)^2]/{(2x-2x+y)/[(2x+y)(2x-y)]}
=2x*(2x-y)/(2x+y)
把x=-3/5,y=2/3代入,得:
-2*3/5*(-2*3/5-2/3)/(-2*3/5+2/3)
=-21/5
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