log2(x+1)=log4x解方程
解方程log4(3x+1)=log4x+log4(3+x)
已知log2[log3(log4x)]=0,求x的值
解方程log2(2-x)=log2(x-1)+1
解方程:log2(x+4)+log2(x-1)=1+log2(x+8)
已知log2[log3(log4x)]=log3[log4(log2y)]=0,求x+y
log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值,
log2[log3(log4x)]=0求解x值.麻烦写在纸上拍给我.
若log2(log3(log4x)=log3(log4(log2y)=log4(log2(log3z)=0则x+y-z=
解方程log2^(4^x+4)=x+log2^[2^(x+1)-3]
解方程log2(4^x+1)=x+log2(2^(x+3)-6)
解方程:log2(4^x+4)=x+log2(2^(x+1)-3)
解方程log4(2-x)=log2(x-1)-1