根号2cos(x-π/4)化简
∫(0~π) x根号(cos^2x-cos^4x) dx 怎么算
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
求定积分∫(π/2,-π/2) 根号cos^x-cos^4x dx
化简sin(x+π/2)分之1+根号二cos(2x-π/4)
根号2/4sin(π/4-x)+根号6/4cos(π/4-x) 化简
化简 根号3sinXcosX+cos*2X
化简lg[cos(2π-x)cot(3π/2-x)+1-2xin^2x/2]+lg[根号2cos(x-π/4)]-lg[
求化简f(x)=sin^2x+2根号3sin(x+π/4)cos(x-π/4)-cos^2x-根号3
f(x)=sin平方x+2根号3sin(x+π/4)cos(x-π/4)-cos平方x-根号3
化简 1/2cos x-根号3/2sin x 根3sin x+cos x
已知f(x)=cos^4x-2根号3sinxcosx-sin^4x 化简
化简:3/2cos x-(根号3)/2sin x