根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2] = 12

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根号下[x^2+(y+4)^2] + 根号下[x^2+(y-4)^2] = 12
√[x^2+(y+4)^2] + √[x^2+(y-4)^2] = 12
[x^2+(y+4)^2] + 2√[x^2+(y+4)^2][x^2+(y-4)^2] +[x^2+(y-4)^2] = 144
x^2+y^2+8y+16 + 2√[x^2+(y+4)^2][x^2+(y-4)^2] +x^2+y^2-8y+16 = 144
√[x^2+(y+4)^2][x^2+(y-4)^2] =56-x^2-y^2
[x^2+(y+4)^2][x^2+(y-4)^2] =56^2+x^4+y^4-112x^2-112y^2+2x^2y^2
[x^2+(y+4)^2][x^2+(y-4)^2] =56^2+x^4+y^4-112x^2-112y^2+2x^2y^2
x^4+((y+4)^2+(y-4)^2)x^2+(y^2-16)^2=56^2+x^4+y^4-112x^2-112y^2+2x^2y^2
x^4+2x^2y^2+32x^2+y^4-32y^2+16^2=56^2+x^4+y^4-112x^2-112y^2+2x^2y^2
2880-144x^2-80y^2=0
180-9x^2-5y^2=0

(x+y)/(根号下x+根号下y)+2xy/(x根号下y+y根号下x)=______. Y=根号下(2-x)+根号下(3x+12),-4 已知根号下(3x-2y+4)+根号下（x+2y+12)=0,求根号下（x^2+y^2)的值若x,y为实数,且y=x+2分之根号下(x平方-4)+根号下(4-x)平方+1,求根号下x+y x y a满足根号下x+y-8+根号下8-x-y=根号下3x-y-a+根号下x-2y+a+3 若X、Y为实数,且Y=根号下1-4X+根号下4X-1+2分之1,求根号下Y分之X+2+X分之Y-根号下Y分之X-2+X分若x,y为实数,且y=根号下1-4x+根号下4x-1+二分之1,求根号下y分之x+2+x分之y-根号下y分之x-2+x分已知根号下x^2-4x+4 + 根号下y^2+6y+9=0,求y^x y=根号下-x^2+4x的值域数学题：已知x、y、z满足：根号下3x-2y-4+根号下2x-7y+3=根号下2x-4y-z·根号下x/2-x+2y,求计算：（2/3x根号下9x+6x根号下y/x）+（y根号下x/y-x的平方根号下1/x)= 函数y=根号下4 *x^2+4x+1+根号下4*x^2-12x+9