求值：cos(3π/8-θ)cos(5π/24-θ)+sin(π/8+θ)sin(7π/24+θ)

sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π) 求值:已知sinθ+cosθ=1/5,已知θ∈(0,π). θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小 8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值 sin(π-θ）+cos(2π-θ）/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____ 已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4) 求值：sin(π/12)+cos(π/12) 若（sinθ+cosθ）/（sinθ-cosθ）=2,则sin（θ-5π）*sin（3π/2-θ）等于? (sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)= 已知向量m=(cosθ,-sinθ),n=(根号2+sinθ,cosθ),θ∈(π,3π/2),且cos(θ/2+π/8 （sinθcosπ/3）-（cosθsinπ/3）怎么化简得sin(θ-π/3) ①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin(