若x-1的绝对值+(xy-2)²=0
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/29 10:27:42
若x-1的绝对值+(xy-2)²=0
1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2012)(y+2012)
求那个算式的值
1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2012)(y+2012)
求那个算式的值
由 |x - 1| +(xy-2)²=0可知 x - 1 = 0 ,xy - 2 = 0 ,解这两个方程可得 x = 1 ,y = 2
所以:1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2012)(y+2012)
=1/(1×2)+ 1/(2×3) + 1/(3×4)+……+ 1/(2013×2014)
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ……+ 1/2013 - 1/2014
= 1 - 1/2014
= 2013/1014
所以:1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2012)(y+2012)
=1/(1×2)+ 1/(2×3) + 1/(3×4)+……+ 1/(2013×2014)
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ……+ 1/2013 - 1/2014
= 1 - 1/2014
= 2013/1014
若(x²-3xy+y+x-5)+3x+1的绝对值=0,则x²-3xy+y-2=多少
已知绝对值3x+2y+1绝对值+(3x-4y+7)²=0,求xy的值
若x-1的绝对值+(y+3)²=0,求代数式1-xy-xy²的值.
若3x+5的绝对值+(1\3y-2)的平方=0,则xy
已知x-1的绝对值+y-2的绝对值=0,求代数式2x^2-[x^2-(2xy-y^2)+2xy]的值.
已知(x+2)的四次方+y-1的绝对值=0,求5xy-【4x²y-(-3xy²+2x²+2
已知x-1的绝对值+y-3 的绝对值=0,求x+y分之xy
七年级数学题若X-1的绝对值+(XY-2)平方=0,求1/XY+1/(X+1)(Y+1)+1/(X+2)(Y+2)+--
已知(x+1)的平方+y-1的绝对值=0 求2(xy-5xy的平方)-(3xy的平方-xy)的值
已知(x+1)的平方+y-1的绝对值=0,求2(xy-xy的平方)-(3xy的平方-xy)的值
已知(x+y)的平方+(y-1)的绝对值=0,求2(xy-5xy的平方)-(3xy的平方-xy)的值
已知(x+1)平方+y-1的绝对值=0 求2(xy-5xy平方)-(3xy平方-xy)的值