若x²-2y+y²+8y+17=0,则x=?y=?
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
设x>1,y>0,若x^y+x^-y=2根号2,则x^y-x^-y等于
若实数X,Y满足X²+Y²+4X-2Y +1=0,则X²-6X+Y²-2Y的最大
若x²+2x+y²-8y+17=0 求x 的y次方的值~
已知:x²y²-2x+6y+10=0则x+y=
已知x²+4x+y²-2y+5=0,则x+y=
x²-2x+y²+6y+10=0,则x+y=?
(x+y)²-2x-y=0,则(x-y)999次方=?
若x的平方-2y+y的平方+8y+17=0,则x= ,y=
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
已知x,y满足x²+y²-4x+6y+13=0则(3x+y)²-(3x+y)(3x-y)的