SELECT o.partner_id FROM order o LEFT JOIN partner p on p.id

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SELECT o.partner_id FROM order o LEFT JOIN partner p on p.id=o.partner_id LEFT JOIN team t on t.id
$sql="SELECT o.partner_id FROM order o LEFT JOIN partner p on
p.id=o.partner_id LEFT JOIN team t on t.id=o.team_id where
o.state='pay' and o.pay_time >= 1364313600 and (( o.rstate =
'askrefund' and o.allowrefund = 'Y') or o.allowrefund = 'N') and
o.pay_time

order by后面的字段不在select字段里面

sql 中 select * from A left join B on A.id=B.id where A.id=?如 sql函数,select count(A.abc) as sum from A left join B on A.id= 请问sql="select * from 招聘信息 order by id select count(*) as total from 'test' order by id desc select top 10 * from (select top 40 * from a order by id asc sql = "Select * from product_series order by index desc,id a 请教sql语句,像select …from wsdy_zb t where t.id =:id order by no ORACLE 中 select B.f from a A left join b B on A.e=B.e 如果B.f为 $sql = "select tb_note.*,answ.* from tb_note left join";这句话解输出功率 P.M.P.O. l left home at nine o'clock p.m.对at nine o'clock p.m提问 P.O. No 是什么意思?