∫∫sin x / x dx dy

∫(1,2)dx∫(√x,x)sin(πx/2y)dy+∫(2,4)dx+∫(√x,2)sin(πx/2y)dy 求∫dy/(2sin(y/2))=-∫sin(x/2)dx sin(xy)=x 求dx/dy ∫dy/ylny=∫dx/x 计算二次积分∫(0,1)dy∫(√y,1)sin x^3 dx 计算二次积分:∫(1,3)dx∫(2,x-1)sin(y^2)dy y＝∫（x 1）sin（t∧2）dt,求dy/dx y＝∫（1 -x）sin（t∧2）dt,求dy/dx y=sin[sin(x^2)] 则dy/dx=? x=sin(y/x)+e^2 求dy/dx d{cos(x-y)=sin(x-y)(dx-dy)这里dx-dy是什么意思呢? 计算二重积分∫（0~1）dx∫（x²~1）x³sin（y³）dy