y=x+z,y-x=2,x+10y+100z+99=z+10y+100x,联立这三个等式,答案是：x=3,y=5,z=2

X-Y-Z=4 3Y-X-Z=8 7Z--X-Y=16 这三个方程联立求x y z (x+y-z)(x-y+z)= 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) x/2=y/3=z/5 x+3y-z/x-3y+z (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai X+Y+Z=? 若{x+3y+10z=0 则 (x+y-z)/(x-y+z) 3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5 {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 解一道三元一次方程x+y+z=13,y-2=z,100z+10y+x+99=100x+10z+y. 已知x^3+y^3-6x+2y+z+3+10=0,求（x-y+z)(x+y-z)的值.（z+3)是绝对值 (x+y-z)^2-(x-y+z)^2=?