化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)s

(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π 已知(3sinα+cosα)/(3cosα-sinα)=2,则2-3sin（α-3π）sin（1.5π-α）-[cos（ 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α- 1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α) 比较大小sin(cosα)与cos(sinα)（0＜α＜π/2) α∈（0,π／2 ）,比较 sin(cosα) 与cos(sinα)大小 化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)= 化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π 已知tan（π-α）=2,求sin²α-2sinαcosα-cos²α/4cos²α-3s 已知α∈（0,π/2),且2sinα-sinαcosα-3cosα=0.求[sin(α+π/4)]/[sin2α+cos 设f(α)=2sinαcosα+cosα/1+sin²α+cos(3π/2+α)-sin²(π/2+ 已知tan（3π+α）=2,求：1、（sinα+cosα）²；2、sinα-cosα/2sinα+cosα