x2+x=13 y2+y=13 x+y-3=?

已知x2+y2+4x-6y+13=0 求x2-2x\x2+3y2 已知x2+y2-6x+4y+13=0,求2x+3y 已知x2+y2+4x-6y+13=0 我做对了吗.x2(x-y)+y2(y-x)= x2(x-y)-y2(x-y)=x2-y2=(x+y）（x-y） 1.已知X2+Y2-4X-6Y+13=0,求Y2-X2的值 已知x2-4x+y2-6y+13=0求x2+y2的值? 已知2x=3y,求xy／(x2+y2)-y2／(x2-y2)的值 x2-x-y2-y 解法：=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1) 已知x2-4x+y2+6y+13=0,求x-y的值 已知实数x,Y满足x2+y2+4x-6y+13=0,则x(-Y)= 已知:实数x、y满足x2+y2-4x-6y+13=0则y的x次方= 已知：x2+4x+y2-6y+13=0,求（x-2y)/（x²+y²）