x0>x1>x2>x3>0,log(x0/x1)1993+log(x1/x2)1993+log(x2/x3)1993>=

min=x1*log(x1)+x2*log(x2)+x3*log(x3)；约束是x1+x2+x3=1; 为什么在ling log(y)=c1+c2*log(x1)+c3*log(x2)+c4*log(x3)这个函数用spss能求出解吗? 设X1,X2,X2是方程X3+PX+q=0的3个根,计算行列式 X1 X2 X3 X3 X1 X2 X2 X3 X1 已知x1,x2,x3∈（0,+∞）,且x1+x2+x3=1.求证x1^2/(x1+x2)+x2^2/(x2+x3)+x3 令x0=a,x1=b,x2=x0+x1/2=a+b/2,x3=x1+x2/2,x4=x2+x3/2,x5=x4+x3/2 设线性方程组 x1+x2+x3=0 x1,x2,x3是方程x^3+px+q=0的根,求三阶行列式x1 x2 x3,x3 x1 x2,x2 x3 x1的值 X2/X1(X1+X2)+X3/(X1+X2)(X1+X2+X3)+.Xn/（x1+x2+...Xn-1)(X1+X2. 线性代数:实数向量空间v=｛（x1,x2,x3)|x1+x3=0}的维数是?v=｛（x1,x2,x3)|x1+x2+x3 x1,x2,x3,是x^3+px+2=0的三个根,计算行列式 :|x1 x2 x3| |x2 x3 x1| |x3 x1 求线性方程组 x2-x3-x4=0 x1+x2-x3+3x4=1 x1-x2+x3+5x4=-1 x1+2x2-2x3+ 设X1,X2,X3是方程X^3+px+q=0de三个根,则|x1 x2 x3|= |x3 x1 x2| |x2 x3 x