数学x²+y²-10x+12y+61=0,求x+y

x²+4y²-2x+12y+10=0求X,Y值 已知x^2+y^2-10x-12y+61=0,求x/y-y/x的值 已知实数x, y满足x²+y²-2x+6y+10=0,求y∧-x. 若|x+2y-1|+y²+4y+4=0,求（2x-y）²-2（2x-y)(x+2y)+(x+2y)& 已知x²+y²-8x+6y+25=0,求（x-y+4xy/x-y）（x+y-4xy/x+y） 已知非零有理数x,y满足x²-4xy+4y²=0,求x-y/x+y-y-x/x+y的值. 已知y+y'*x²=0,求y=? 若|x+y-1|+（x-y-2)²=0,求代数式（x+2y)(x-2y）-（2x-y)(-y-2x)的值. 当x,y为实数,满足x²+3y²-12y+12=0求y^x 已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y² 已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y (4xy-2y²)/4 求x²+y²-2x+4y+1的最小值 求x,y的值 x²+2xy+4x-12y+22=0