sin（x+π/6）=3/5,则cos(2x+π/3)=

已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3）+cos平方x. 求证 tan（2π-X）sin（-2π-X）cos（6π-X）/ sin（X+3π/2)*cos（X+3π/2)=-ta 已知cos(π/2+x)=sin(x-π/2) 求sin^3(π-x)+cos(x+π)/5cos(5π/2-x)+3s 已知函数f(x)=cos(2x-π/3）+2sin(x-π/4）sin(x+π/4)=sin(2x-π/6) , 已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x 已知函数f(x)=cos(2x-π\3)+sin²x-cos²x cos(π/6-x)=根号3/3则cos(5π/6+x)-sin(x-π/6)的平方 已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)] 函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值 若sin(π/2+x)=-4/5,x属于（π/2,π）,则cos(π/3-x)= f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx 已知函数f(x)=cos(π/6-2x)+cos(2x+π/6)+sin(2x+π/3)-sin(π/3-2x).