数学题(2x+3y-7)(2x+3y+2)+20
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/10/08 04:24:15
数学题(2x+3y-7)(2x+3y+2)+20
=(2x+3y)^2-5(2x+3y)+6
=(2x+3y-2)(2x+3y-3)
再问: 还有两题。。。等下给你加分 1. (x+y)(6x+6y-1)-1 2. x(x-1)(x+1)(x+2)-24
再答: 1. =(x+y)(6(x+y)-1)-1 =6(x+y)^2-(x+y)-1 =(3x+3y+1)(2x+2y-1) 2. =(x^2+x)(x^2+x-2)-24 =(x^2+x)^2-2(x^2+x)-24 =(x^2+x-6)(x^2+x+4) =(x+3)(x-2)(x^2+x+4)
=(2x+3y-2)(2x+3y-3)
再问: 还有两题。。。等下给你加分 1. (x+y)(6x+6y-1)-1 2. x(x-1)(x+1)(x+2)-24
再答: 1. =(x+y)(6(x+y)-1)-1 =6(x+y)^2-(x+y)-1 =(3x+3y+1)(2x+2y-1) 2. =(x^2+x)(x^2+x-2)-24 =(x^2+x)^2-2(x^2+x)-24 =(x^2+x-6)(x^2+x+4) =(x+3)(x-2)(x^2+x+4)
数学题……555{(3x+y)(3x-y)-(x-5y)(5x-y)-(x-2y)²÷(-4x),x=-2.y
数学题(x+y+3)(x^2+y^2+2xy-3x-3y+9)
问个数学题,(2x+3y)^2-(2x+y)(2x-y)
数学题(2x+y):(x+2y)=2:3,x:y得多少
求解初中数学题(x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y
求两个数学题怎么解答..1.写出x、Y的关系式 x:-1 y:3 x:0 y:0 x:1 y:-3 x:2 y:-6 x
数学题化简再求值(1/x-y+1/x+y)÷x^2 y^2/x^2-y^2,其中x=3,y=-√2
化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方
【x-3y][x+y]-[x-2y][x +2y]-[x-y
[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)
(-3x+7y)(-7y-3x)-(x-3y)(2x+3y)
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20