三角函数方程问题Solve the following equation for 0°≤x≤360°.(Give the
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三角函数方程问题
Solve the following equation for 0°≤x≤360°.(Give the answers correct to 1 decimal place if necessary.)
-2 tan ( 3x + 6° ) = 1
Solve the following equation for 0°≤x≤360°.(Give the answers correct to 1 decimal place if necessary.)
-2 tan ( 3x + 6° ) = 1
-2tan(3x+6°)=1
tan(3x+6°)=-1/2
0°≤x≤360°
0°≤3x≤1080°
6°≤3x+6°≤1086°
The reference angle is 3x+6°=arctan(-1/2)≈-26.5651°
∵tan(3x+6°)
tan(3x+6°)=-1/2
0°≤x≤360°
0°≤3x≤1080°
6°≤3x+6°≤1086°
The reference angle is 3x+6°=arctan(-1/2)≈-26.5651°
∵tan(3x+6°)
solve the equation .
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