log(2x – 3)(x2－3)＞0

函数y＝log 12 (3＋2x－x2)的值域是__________． 求y=log½(3+2x－x2)的值域 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x 解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6)) 已知log(1/7)[log(3)(log(2)x)]=0 函数f(x)=log(x2-2x+3)定义域 值域 单调区间 解方程[log(a)(x-1)]-[log(a)(2x-3)]=log(a)(1/3-x),(a＞0,且a≠1). log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log( 求函数y=log(x-1)（-X2+2X+3）的定义域.括号里那是x的平方 已知log的2次方【log的3次方（log的4次方x)】=log【log的4次方（log的2次方y】=0,求x+y的值