1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11)+1/(9*11*13)+1/(11*1
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/10/01 00:41:39
1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11)+1/(9*11*13)+1/(11*13*15)等于多少
原式=[1/(3*5)]*[1+1/7]+[1/(7*9)]*[1/5+1/11]+[1/(11*13)]*[1/9+1/15]
=8/(15*7)+16/(15*7*33)+8/(9*11*65)
=[8/(3*5*7)]*[1+2/33]+8/(9*11*65)
=8/99+8/(99*65)
=[8/99]*[1+1/65]
=[8/99]*[66/65]
=16/195
=8/(15*7)+16/(15*7*33)+8/(9*11*65)
=[8/(3*5*7)]*[1+2/33]+8/(9*11*65)
=8/99+8/(99*65)
=[8/99]*[1+1/65]
=[8/99]*[66/65]
=16/195
计算:1/3*5+1/5*7+1/7*9+1/9*11+1/11*13
1 -3 5 -7 9 -11 13
计算:2/3*5+1/5*7+1/7*9+1/9*11+1/11*13
简便计算1/1*3*5+1/3*5*7+1/5*7*9+1/7*9*11+1/9*11*13+1/11*13*15中1/
1×3/1+3×5/1+5×7/1+7×9/1+9×11/1+11×13/1简便运算
1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11)+1/(9*11*13+)1/(11*1
1/1*3*5+1/3*5*7+1/5*7*9+1/7*9*11+1/9*11*13+1/11*13*15怎么计算
简算:1/1*3+1/3*5+1/5*7+1/7*9+1/9*11
(1/3+1/5+1/7+1/9)*(1/5+1/7+1/9+1/11)-(1/3+1/11+1/5+1/7+1/9)*
(1/5+1/7+1/9+1/11)*(1/7+1/9+1/11+1/13)-(1/5+1/7+1/9+1/11+1/1
1/3+1/5+1/7+1/9+1/11+1/13+1/15=
3*5分之1+5*7分之1+7*9分之1+9*11分之1+11*13分之1