printf("\n%ld/%ld=809*%line(x 6,y 20,x 10,y 18);

#include main( ) {int x,y; scanf("%2d%ld",&x,&y); printf("%d int x=10,y=20; main() {func();printf("%d,%d\n",x,y);} func() main() { int x=10; int y=x++; printf("%d,%d\n",(x++,y),y++); 若有说明int x=10,y=20;请写出各printf语句的输出结果 printf(“%3o\n”,x%y,x,y) main() { int x=2002,y=2003; printf("%d\n",(x,y)); } 为什么结果是20 printf("x=%d,y=%d\n",x,y);中\n的作用是啥? int x=1,y=1; printf("%d\n",(y=1)==0)&&((x=6)==6)); printf("% while (scanf(\"%ld %ld %ld\",&a,&b,&c) == 以下程序的输出结果是() int x=10,y=10;printf("%d %d\n",x--,--y); main( ) { int x=010,y=10,z=0x10; printf(“%d,%d,%d\n”,x,y,z); int x=3,y=2,z=1;printf("%d\n",x/y&~z) 设有如下程序段：int x=2002,y=2003;printf("%d\n",(x,y))