eviews cd 函数模型时为什么log(q)=c(1)+c(2)*t+c(3)*log(l)+c(4)*log(k)
对数函数题 log a - log b = 3 log (c/2) 求 a = ______________
用C语言计算log(5)log(3)-log(2))/sin(π/3)=
利用对数的换底公式化简下列 1.log(a)c×log(c)a 2.log(2)3×log(3)4×log(4)5×lo
利用换底公式证明:log(a)b.log(b)c.log(c)a=1
log a b*log b c=log b b*log a c成立吗
a^[log(a)b×log(b)c×log(c)N]
2log(b)x=log(a)x+log(c)x
a=log(3)π b=log(7)6 c=log(2)0.8 哪一个大,
log(2)(a)=log(3)(b)=log(5)(c)
[log (底数为a) x]=[1\2log (底数为a) b ] - [ log (底数为a)c]求X
log(a)(b)=log(c)(b) /log(c)(a) 怎么证
2^a=log(1/2)a,(1/2)^b=log(1/2)b,(1/2)^c=log(2)c,比较a,b,c的大小