lim(x→0)[(secx)^2-1] /(1-cosx)
lim[ln(1+x^2)]/(secx-cosx) x->0
求极限lim x→π(sin3x)/(x-π)和求极限lim x→π/2(1+cosx)secx
1、lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
lim(x趋于0时)secx - 1/x^2 ,
limx趋向0[ln(1+x^2)/secx-cosx]
lim下标x到二分之派,然后(1加cosx)3secx次幂求极限
求Lim(x→0)(sinx/x)^(cosx/1-cosx)
lim x→0 1-cosx/xsinx
lim(x→0)(1/cosx)=?
lim(x→0)(cosx)^(1/ln(1+x^2))
lim(x→0)(ln(1+x^2)/(sec-cosx))