化简sin(3π-α)/[sin(-α-2π)]+cos(4π-α)/[cos(α-5π)]+tan(-α)/[tan(
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
求证:[sin^2(π+α)*cos(π/2-α)+tan(2π-α)*cos(-α)]/-sin^2(-α)+tan(
已知tan(α+π/4)=2,则(2sinα+cosα)/(3cosα-2sinα)
已知tan(α+π/4)=2,求2cosα-sinα/cosα+3sinα
已知tan(α+π/4)=3,求cosα+2sinα/cosα-sinα的值
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
已知tan(π-α)=2,求sinα-2sinαcosα-cosα/4cosα-3sinα的值
已知sin a=2cos a 计算⑴(sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4)
化简sin³(﹣α)cos(2π+α)tan(2π-α)/sin(α-2π)cos(α-3π/2)-tan(π
证明[2-2sin(α+3π/4)cos(α+π/4)]/(cos^4α-sin^4α)=(1+tanα)/(1-tan
已知tanα/2=2,求(1)tan(α-4/π)的值,(2)(3sinα+cosα)/(3cosα-sinα)
已知tanα/2=2,1.求tan(α+π/4)的值 2.(6sinα+cosα)/(3sinα-2cosα)的值