An object of mass m = 6.05 kg has an acceleration a = (1.17
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An object of mass m = 6.05 kg has an acceleration a = (1.17 m/s2)x + (-0.664 m/s2)y.Three forces act on this object:F1,F2,and F3.Given that F1 = (2.96 N)X and F2 = (-1.55 N)x + (2.05 N)y,find F3.
F3=( )X + ( )Y?
F3=( )X + ( )Y?
力的分解,由牛顿运动定律,在x方向上F1+F2+F3=ma(x)解得F3在x方向上是5.6685.同理在y方向上F1+F2+F3=ma(y)解得F3在y方向上是-6.0672
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