∫sec^2 x / √ tan x +1 dx

∫sec^4x dx ∫sec^2x tan^2x dx 求不定积分（1）dx/√x(1+√x)（2）dx/e^x+（e^-x）+2 (3)(tan^5x*sec^4x)dx ∫tan^2xdx=∫(sec^2x-1)dx ∫secx/sec^2x-1 dx ∫ sec^2 x dx ∫(tan^(5)(x)*sec^(4)(x))dx 求积分∫（sec^2x/2+tan^2x）dx ∫cosx cos3x dx ∫tan^3t sect dt ∫(sec^2x)/4+tan^2 dx ∫1/根号x*sec^2(1-根号x)dx ①∫tan^10×sec^2xdx②∫[x/√(x^2-2)dx③∫[(2x-3)/(x^2-3x+8)]dx④∫(1/ ∫sec²x/1+tanx dx ∫（sec^2x+sinx)dx